4x^2+45x=36

Solution for 4x^2+45x=36 equation:

4x^2+45x=36

We move all terms to the left:

4x^2+45x-(36)=0

a = 4; b = 45; c = -36;
Δ = b2-4ac
Δ = 452-4·4·(-36)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-51}{2*4}=\frac{-96}{8}
=-12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+51}{2*4}=\frac{6}{8}
=3/4
$